Optimal. Leaf size=180 \[ \frac{78 e^7 \sin (c+d x) \sqrt{e \cos (c+d x)}}{7 a^4 d}+\frac{234 e^5 \sin (c+d x) (e \cos (c+d x))^{5/2}}{35 a^4 d}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4 \sin (c+d x)+a^4\right )}+\frac{78 e^8 \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 a^4 d \sqrt{e \cos (c+d x)}}+\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a \sin (c+d x)+a)^3} \]
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Rubi [A] time = 0.175337, antiderivative size = 180, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.16, Rules used = {2680, 2635, 2642, 2641} \[ \frac{78 e^7 \sin (c+d x) \sqrt{e \cos (c+d x)}}{7 a^4 d}+\frac{234 e^5 \sin (c+d x) (e \cos (c+d x))^{5/2}}{35 a^4 d}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4 \sin (c+d x)+a^4\right )}+\frac{78 e^8 \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 a^4 d \sqrt{e \cos (c+d x)}}+\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a \sin (c+d x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 2680
Rule 2635
Rule 2642
Rule 2641
Rubi steps
\begin{align*} \int \frac{(e \cos (c+d x))^{15/2}}{(a+a \sin (c+d x))^4} \, dx &=\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a+a \sin (c+d x))^3}+\frac{\left (13 e^2\right ) \int \frac{(e \cos (c+d x))^{11/2}}{(a+a \sin (c+d x))^2} \, dx}{a^2}\\ &=\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a+a \sin (c+d x))^3}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4+a^4 \sin (c+d x)\right )}+\frac{\left (117 e^4\right ) \int (e \cos (c+d x))^{7/2} \, dx}{5 a^4}\\ &=\frac{234 e^5 (e \cos (c+d x))^{5/2} \sin (c+d x)}{35 a^4 d}+\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a+a \sin (c+d x))^3}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4+a^4 \sin (c+d x)\right )}+\frac{\left (117 e^6\right ) \int (e \cos (c+d x))^{3/2} \, dx}{7 a^4}\\ &=\frac{78 e^7 \sqrt{e \cos (c+d x)} \sin (c+d x)}{7 a^4 d}+\frac{234 e^5 (e \cos (c+d x))^{5/2} \sin (c+d x)}{35 a^4 d}+\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a+a \sin (c+d x))^3}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4+a^4 \sin (c+d x)\right )}+\frac{\left (39 e^8\right ) \int \frac{1}{\sqrt{e \cos (c+d x)}} \, dx}{7 a^4}\\ &=\frac{78 e^7 \sqrt{e \cos (c+d x)} \sin (c+d x)}{7 a^4 d}+\frac{234 e^5 (e \cos (c+d x))^{5/2} \sin (c+d x)}{35 a^4 d}+\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a+a \sin (c+d x))^3}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4+a^4 \sin (c+d x)\right )}+\frac{\left (39 e^8 \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{7 a^4 \sqrt{e \cos (c+d x)}}\\ &=\frac{78 e^8 \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 a^4 d \sqrt{e \cos (c+d x)}}+\frac{78 e^7 \sqrt{e \cos (c+d x)} \sin (c+d x)}{7 a^4 d}+\frac{234 e^5 (e \cos (c+d x))^{5/2} \sin (c+d x)}{35 a^4 d}+\frac{4 e (e \cos (c+d x))^{13/2}}{a d (a+a \sin (c+d x))^3}+\frac{52 e^3 (e \cos (c+d x))^{9/2}}{5 d \left (a^4+a^4 \sin (c+d x)\right )}\\ \end{align*}
Mathematica [C] time = 0.38013, size = 66, normalized size = 0.37 \[ -\frac{2 \sqrt [4]{2} (e \cos (c+d x))^{17/2} \, _2F_1\left (\frac{3}{4},\frac{17}{4};\frac{21}{4};\frac{1}{2} (1-\sin (c+d x))\right )}{17 a^4 d e (\sin (c+d x)+1)^{17/4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.931, size = 225, normalized size = 1.3 \begin{align*} -{\frac{2\,{e}^{8}}{35\,{a}^{4}d} \left ( 80\,\cos \left ( 1/2\,dx+c/2 \right ) \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{8}-120\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{6}\cos \left ( 1/2\,dx+c/2 \right ) -224\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{7}-280\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{4}\cos \left ( 1/2\,dx+c/2 \right ) +336\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{5}+195\,\sqrt{2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}\sqrt{ \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}{\it EllipticF} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) +160\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}\cos \left ( 1/2\,dx+c/2 \right ) +392\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{3}-252\,\sin \left ( 1/2\,dx+c/2 \right ) \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{-2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}e+e}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{e \cos \left (d x + c\right )} e^{7} \cos \left (d x + c\right )^{7}}{a^{4} \cos \left (d x + c\right )^{4} - 8 \, a^{4} \cos \left (d x + c\right )^{2} + 8 \, a^{4} - 4 \,{\left (a^{4} \cos \left (d x + c\right )^{2} - 2 \, a^{4}\right )} \sin \left (d x + c\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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